Question

in fig 5 AB||CD and DE||PF. If angle APF=50 and angle CDG =40 find
a) angle AQD
b) angle EDG
c) angel DPF

Answer 1

Answer :

a)50

b) 90

c) 90

Step-by-step explanation:

DE//PF => EQ//PF so angle AQD is 50 (corresponding angles)

AB//CD so angles DPB=GDC=40

at P Angle FPG +50+40 =180 so FPG = 90

FP// EQ (see first step) angle FPG = EDG =90

(corresponding angles)

Answer 2

Answer:

angle AQD= 50°

angle EDG=90°

angle DPF=90°