Question

In Fig.5 , CB = CD and angle GBA = angle FDE. Using the AAS criteria of congruence, prove that ∆ABC is congruent to ∆EDC.



QUESTION IS FROM CLASS-7TH PLEASE GIVE ME THE CORRECT ANSWER (no foolish answer).​

Answer 1

Answer: IN ΔABC AND ΔEDC

CB = CD ( COMMON )

∠ACB = ∠ECD ( VERTICALLY OPPOSITE ANGLE ARE EQUAL

∠CDE = ∠CAB ( ALTERNATE INTERIOR ANGLE BECAUSE ∠FDE AND ∠GBA ARE EQUAL AND A TRANSVERSAL IS THERE SO AB ║ ED THEN ∠CDE = ∠CAB)

∴ Δ ABC ≅ ΔEDC ( BY AAS OR SAA )

I HOPE IT IS CORRECT

Answer 2

Answer:

MARK AS BRAINLIST

Step-by-step explanation:

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