Question

In Fig. 5, is a decorative block, made up two solids - a cube and a hemisphere. The base of the block is a cube of side 6 cm and the hemisphere fixed on the top has diameter of 3.5 cm. Find the total surface area of the bock. (use $(\pi =\frac{22}{7} )$ )

Answer 1

Hey mate!!
Here's ur answer:


tsa of cube = 6a2
side of cube = 6cm
tsa = 6*36
      = 216
csa of sphere = 2πr2
                            = 2*22/7*3.5/2*3.5/2
                           =19.5cm2
tsa of fig =tsa of cube - area of base of hemishere + csa of hemisphere
               =216-9.75+19.5
                  =225.75cm2


Hope u understand

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Answer 2

Answer:

225.625 cm²

Step-by-step explanation:

Find the total surface area of the cube:

Area = 6 x Length²

Area = 6 x 6² = 216 cm²

Find the base area of the hemisphere:

Area = πr²

Area = π(3.5 ÷ 2)² = 9.625 cm²

Find the area of the hemisphere (without base)

Area = 2πr²

Area = 2(9.625) = 19.25 cm²

Find the total surface area of the figure:

Area = 216 - 9.625 + 19.25 = 225.625 cm²

Answer: 225.625 cm²