Question

In Fig.5, ‘O’ is the centre of a circle and ∠OBA = 60º. Then ∠ACB equals

Answer 1

$\huge{ \bold{ { \colorbox{black}{ \color{lime}{AnsR}}}}}$

$\sf{Consider \:  △AOB. }</em></strong></p><p></p><p><strong><em>[tex] \sf{Consider \:  △AOB. }$

$\sf{OA=OB⇒∠OAB=∠OBA=60°}$

$\sf{By \: angle \: sum \: property , \: we \: get,  \: ∠AOB=60°}$

Angle in subtended at the center is twice the angle subtended anywhere on the arc, so

$\sf{∠ \: ACB= \frac{1}{2} \: \: \: ∠AOB=30°}$

hope its help u