Question

In Fig. 6.1, if AB || CD || EF, PQ || RS, ZRQD
= 25° and ZCQP = 60°, then ZQRS is equal
A
to​

Answer 1

Answer:

145°

Step-by-step explanation:

AB || CD || EF (Given)

PQ || RS  (Given)

∠ RQD = 25° (Given)

∠ CQP = 60° (Given)

According to the figure -

∠ DQR = ∠ QRA = 25° ( Alternate interior angles)

∠ PQC = ∠ BRS = 60°  ( Alternate exterior angles)

∠ QRA + ∠ ARS = ∠QRS  

= ∠QRA + (180° – ∠BRS) [ Linear pair axioms]

= 25° + 180° - 60°

= 205° - 60°

= 145°

Therefore, the value of ∠QRS is 145

Answer 2

Answer:

n Fig. 6.1, if AB || CD || EF, PQ || RS, ZRQD

= 25° and ZCQP = 60°, then ZQRS is equal

A

your answer is 145°

Step-by-step explanation:

hope it's helpful