Question

In Fig. 6.124, AB I EFII CD, angle CEF equals
(A) 100°
(B) 120
(C) 140
(D) 160°
Fig. 6.124
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Answer 1

In the given fig angle CEF = 160

Answer 2

Answer:

construction draw FD perpendicular toCD

angle ECD =20 (CE bisect angle C)

angle c+ angle d + angle f + angle e= 360

20+90+90+x=360

200+x=360

x=360-200

x=160

hence angle CEF is 160