Question

In Fig. 6.13, lines AB and CD intersect at 0.1
ZAOC + 2 BOE = 70° and 2 BOD = 40" find
2 BOE and reflex 2 COE.​

Answer 1

Answer:

• ∠BOE = 30°
• Reflex ∠COE = 250°

Given:

• ∠AOC + ∠BOE = 70°
• ∠BOD = 40°

To Find:

• ∠COE

Solution:

Since AB & CD intersect,

→ ∠AOC = ∠BOD (V.O.A)

→ ∠AOC = 40°

Also,

→ ∠AOC + ∠BOE = 70° (Given)

→ 40° + ∠BOE = 70°

→ ∠BOE = 70°−40°

→ ∠BOE = 30°

Now,

→ ∠AOC + ∠COE + ∠BOE = 180° (Linear pair)

→ ∠COE + (∠ADC + BOE) = 180°

→ ∠COE + (40° + 30°) = 180°

→ ∠COE + 70° = 180°

→ ∠COE = 180° − 70°

→ ∠COE = 110°

Reflex ∠COE = 360° - 110°

= 250°

Hence,

• ∠BOE = 30°
• Reflex ∠COE = 250°