In fig. 6.13 , lines AB and CD intersect at O. if angle AOC + angle BOE = 70° and angle BOD = 40° , find angle BOE and reflex angle COE
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Answer:
- ∠BOE = 30°
- Reflex ∠COE = 250°
Step-by-step explanation:
Given:
- ∠AOC + ∠BOE = 70°
- ∠BOD = 40°
To Find:
- ∠BOE
- Reflex ∠COE
By Linear pair,
⇒ ∠AOC + ∠BOE + ∠COE = 180°
⇒ 70° + ∠COE = 180°
⇒ ∠COE = 180° - 70°
⇒ ∠COE = 110°
Now, again by linear pair.
⇒ ∠COE + ∠BOE + ∠BOD = 180°
⇒ 110° + ∠BOE + 40° = 180°
⇒ 150° + ∠BOE = 180°
⇒ ∠BOE = 180° - 150°
⇒ ∠BOE = 30°
Hence, ∠BOE = 30°
Again by linear pair,
⇒ ∠AOD + ∠BOD = 180°
⇒ ∠AOD + 40° = 180°
⇒ ∠AOD = 180° - 40°
⇒ ∠AOD = 140°
Now, we will find reflex ∠COE
⇒ Reflex ∠COE = ∠AOC + ∠AOD + ∠BOD + ∠BOE
⇒ Reflex ∠COE = 40° + 140° + 40° + 30°
⇒ Reflex ∠COE = 250°
Hence, Reflex ∠COE = 250°
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