Question

In Fig. 6.13. lines AB and CD intersect at o. In
AOC + BOE = 70° and 2 BOD = 40º find
BOE and reflex 2 COE.
Fig. 6.13​

Answer 1

Step-by-step explanation:

Given:∠BOD=40 =

Since AB and CD intersects, ∠AOC=∠BOD(vertically opposite angles)

∠AOC=40 °

Also,∠AOC+∠BOE=70 °

⇒∠BOE=70 °

−∠AOC=70 °

−40 °

=30 °

We need to find reflex∠COE

Reflex∠COE=360 °

−∠COE

Now, ∠AOC+∠COE+∠BOE=180 °

⇒∠COE+(∠AOC+∠BOE)=180 °

⇒∠COE+(40 °

+30 °

)=180 °

⇒∠COE=180 °

−70°

=110 °

Reflex∠COE=360°

−110°

=250°

Hope this hlp you

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