Question

In Fig. 6.15, angle PQR = angle PRQ, then prove that
angle PQS = angle PRT.

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Answer 1

Step-by-step explanation:

can please give the figure pls

Answer 2

Step-by-step explanation:

maybe

it is isosceles triangle theorem

Theorem : Angles opposite to the equal sides of an isosceles triangle are also equal.

Proof: Consider an isosceles triangle ABC where AC = BC.

We need to prove that the angles opposite to the sides AC and BC are equal, that is, ∠CAB = ∠CBA.

Isosceles Triangle

We first draw a bisector of ∠ACB and name it as CD.

Now in ∆ACD and ∆BCD we have,

AC = BC (Given)

∠ACD = ∠BCD (By construction)

CD = CD (Common to both)

Thus, ∆ACD ≅∆BCD (By SAS congruence criterion)

So, ∠CAB = ∠CBA (By CPCT)

Hence proved.

figure is above refer this theorem