Question

In fig 6.17 POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that
Angle ROS= 1by2 (angle QOS-angle POS)​

Answer 1

Step-by-step explanation:

/POS+/SOQ=180• (L. P)

/POS+/SOR=90•

2(/POS+/SOR) =180•

(Since:POS+ROS=90•)

or, 2(/POS+/SOR) =/POS+/SOQ

or, 2/POS+2/SOR=/POS+/SOQ

or, /POS+2/ROS=/SOQ

or, 2/ROS=/SOQ-/POS

or, /ROS= 1/2 ANGLE SOQ -ANGLE POS