In fig.6.18, if LM is parallel to CB and LN is parallel to CD,prove that am/ab=an/ad
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Answered by
67
In the given figure, LM || CBBy using basic proportionality theorem, we get,
AM/MB = AL/AC ... (i)
Similarly, LN || CD
∴ AN/AD = AL/AC ... (ii)
From (i) and (ii), we get
AM/MB = AN/AD
AM/MB = AL/AC ... (i)
Similarly, LN || CD
∴ AN/AD = AL/AC ... (ii)
From (i) and (ii), we get
AM/MB = AN/AD
Answered by
13
Answer:
By Thales theorem or basic propositionality Theorem
IN∆ABC
LM||BC so by B.P.T
AL/AC=AM/AB-----------(1)
IN∆ADC
AL/LC=AN/AD------(2)
from equation 1 &2 L.H.S is same so R.H.S will also same.
so
AM/AB=AN/AD
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