Question

In Fig. 6.21, AC = AE, AB = AD and angle BAD = EAC. Show that BC = DE


don't answer half​

Answer 1

Step-by-step explanation:

refer to the attachment for answer.

pls folløw ❤️

Answer 2

Answer:

$\huge \sf{\underbrace{\underline{Answer: -}}}$

♧Given:-

• AC=AE,AB=AD and
• $< BAD = < EAC$

♧To prove :-

• BC=DE.

♧Solution :-

• In the question given that the,
• $< BAD = < EAC$

♧Lets,

• Add
• $< DAC \: on \: both \: sides)$
• we get,
• $< BAC = <DAE$

• Considering these two triangles we get that,

• AB=AD(Given)
• <BAC=<DAE(Proved in above]
• AC=AE(Given )

• By SAS congruency in these two triangles we get that,
• BC=DE(According to CPCT)

♧Hence, these is proved.

♧Hope it helps u mate .

♧Thank you .