In Fig. 6.28. find the values of x and y and then
show that ABCD
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Answer:
∠EOA + \angle{x}∠x = 180° [ \therefore∴ liner pair ]
→ 50° + x = 180°
→ x = 180° - 50°
→ x = 130°
Now,
\angle{x}∠x = 130°
\therefore∴ \angle{x}∠x = \angle{CQF}∠CQF = 130°
And
\angle{CQF}∠CQF = \angle{y}∠y [ \therefore∴ Vertically opposite angles ]
Hence,
x = y = 180°
so, they are alternate interior angles
[ \therefore∴ AB ll CD (verified) ]
Step-by-step explanation:
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