Question

in fig.6.32, if AB parallel to CD , angle APQ= 50degree and angle PRD=127degree, find x and y

Answer 1

Here , AB is parallel to CD and transversal PQ intersects them at P and Q respectively.

Therefore, angle PQR = angle APQ (alternate
angles)
=> x= 50° ( given )

Also, AB is parallel to CD and transversal PR intersects them at P and R respectively.

Therefore, APR = PRD (Alternate angles)
=> APQ +QPR= 127° ( PRD = 127°)
=> 50°+y = 127° (APQ = 50°)
=> y = 127° - 50° = 77°

Hence, x = 50° and y = 77°

Hope this will help u .

If helped plz mark it as brainliest answer . PLZ..

Answer 2

Hello mate ☺

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Solution:

AB∥CD, ∠APQ=50° and ∠PRD=127°  (Given)

∠x=50°=∠APQ       (Alternate Interior Angles)

∠APR=∠PRD          (Alternate Interior angles)

⇒50°+∠y=127°

⇒∠y=127°−50°=77°

Therefore, ∠x=50° and ∠y=77°

I hope, this will help you.☺

Thank you______❤

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