Question

In fig.6.38,AOB is line ,if x:y:z=3:4:5, find the value of x,y and z
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Answer 1

Answer:

Given x:y:z=5:4:6  and XOY is a straight line.

Let x=5t;y=4t;z=6t

5t+4t+6t=1800

15t=1800

t=120

So, 

x=5×120=600;y=4×120=480;z=6×120=720.