Question

In Fig. 6.39, sides QP and RQ of ∆ PQR are produced to points S and T respectively. If ∠ SPR = 135° and ∠ PQT = 110°, find ∠ PRQ.​

Answer 1

Given :

• ∠SPR = 135°
• ∠PQT =110°

To Find :

• ∠PRQ

Solution :

$\longmapsto\tt{\angle{PQT}+\angle{PQR}=180\degree}$

${\longmapsto\tt110\degree+\angle{PQR}=180\degree}$

$\longmapsto\tt{\angle{PQR}=180\degree-110\degree}$

$\longmapsto\tt\bold{\angle{PQR}=70\degree}$

Now ,

$\longmapsto\tt{\angle{SPR}=\angle{PQR}+\angle{PRQ}(Exterior\:angle)}$

$\longmapsto\tt{135\degree=70\degree+\angle{PRQ}}$

$\longmapsto\tt{135\degree-70\degree=\angle{PRQ}}$

$\longmapsto\tt\bold{\angle{PRQ}=65\degree}$

So , ∠PRQ = 65°..

Answer 2

Answer:

may this answer help you bro

my writing is not so good