Question

in fig 6.4, if PQ II ST, < PQR= 110° AND < RST = 130°. Find < QRS​

Answer 1

Answer:

it is given that PQ | | ST

draw a line xy | | ST

show x y | | PQ i.e PQ | | St | | x y ..

since PQ | | XY & QR the transversal .

So Δ PQX + Δ QRS = 180

110+ ΔQRS = 180

ΔQRS = 180-110 = 70.

... I hope it's helpful for you

Thanks!