Question

In fig 6.40 = angle 62°,angle 62° ,angle XYZ = 54°, if YO and ZO are the bisects of angle XYZ respectively of triangle XYZ ,find angle OZY and YOZ?​

Answer 1

Step-by-step explanation:

We know that the sum of the interior angles of the triangle.

So, X +XYZ +XZY = 180°

Putting the values as given in the question we get,

62°+54° +XZY = 180°

Or, XZY = 64°

Now, we know that ZO is the bisector so,

OZY = ½ XZY

∴ OZY = 32°

Similarly, YO is a bisector and so,

OYZ = ½ XYZ

Or, OYZ = 27° (As XYZ = 54°)

Now, as the sum of the interior angles of the triangle,

OZY +OYZ +O = 180°

Putting their respective values, we get,

O = 180°-32°-27°

Hence, O = 121°

Answer 2

Answer:

O=121 degree hope this answer help you