In fig 6.41 if AB ll DE, <bac=35degree and <cde = 53 degree, and find <dce
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1
Answer:
<dce = 90°
Step-by-step explanation:
bac = 35°
cde = 53°
so, acd = 90°
alternative angle of acd = dce
so , dce =90°
Answered by
4
Answer:
<DCE =92°
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