Question

In fig 6.43 if pq perpendicular PS pq ll sr, <sqr=28 degree and <Qrt =65degree then find the value of x and y​

Answer 1

Answer:

x=37 and y=53

Step-by-step explanation:

where QR is a transversal

so anglePQR = Angle QRT

X+28= 65

x=37

and PQS is a right angled triangle

sum of three angle is 180

90+37+y=180

y=53.