In Fig. 6.44, the side QR of ΔPQR is produced to a point S. If the bisectors of PQR and PRS meet at point T, then prove that QTR = ½ QPR.In Fig. 6.44, the side QR of ΔPQR is produced to a point S. If the bisectors of PQR and PRS meet at point T, then prove that QTR = ½ QPR.
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Given, Bisectors of ∠PQRand ∠PRS meet at point T.
To prove: ∠QTR=
2
1
∠QPR.
Proof,
∠TRS=∠TQR+∠QTR (Exterior angle of a triangle equals to the sum of the two interior angles.)
⇒∠QTR=∠TRS−∠TQR --- (i)
Also ∠SRP=∠QPR+∠PQR
2∠TRS=∠QPR+2∠TQR
∠QPR=2∠TRS−2∠TQR
⇒
2
1
∠QPR=∠TRS−∠TQR --- (ii)
Equating (i) and (ii),
∴∠QTR=
2
1
∠QPR [henceproved]
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