Question

IN FIG 6.85, BC IS PARALLEL TO EF AND IF ANGLE ABC = 110° AND ANGLE AEF = 50°, FIND ANGLE EAB​

Answer 1

Answer:

Extend Ab and join to EF

so we can name the point joining Ab and EF

is P

so BC is parallel to PF

Angle BPF is 110

Extrerior angle property

answer 69

Answer 2

Draw BD parallel to EF
Now, angle ADB = angle AEF = 50 (corresponding angle)
Therefore, angle ADB + angle DAB = angle ABC (sum of interior angles = exterior angle)
50 + angle DAB = 110
angle DAB = 110 - 50
angle DAB = 60
Now, angle EAB = angle DAB = 60