Question

In Fig. 6.9, lines PQ and RS
intersect each other at point 0. If angle POR: angle ROQ = 5:7, find all the angles.
​

Answer 1

Answer:

angle POR+angleROQ=180° [as they are straight angles]

again angle POR : angle ROQ= 5 : 7

angle POR=5×180°/(5+7)=5×180°/12=5×15°=75°

angle ROQ=7×180°/(5+7)=7×180°/12=7×15°=105°

angle POS=angle ROQ=105° [ opposite angles

angle SOQ=anglePOR=75° [ opposite angles