in fig 6.91, AB is parallel to CD. find the value of x
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Make a line RP parallel to CD and AB containing point E
angle DCE = CER ( alternative interior angle ) eq-1
angle CER = CEB + BER
angle 100° = 40° + BER
BER = 100-40
BER = 60° (eq - 2 )
angle ABE + BER = 180° ( co - interior angel)
ABE = 180° - BER
ABE = 180° - 60°
ABE = 120°
hope it helps
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☞Make a line RP parallel to CD and AB containing point E
➩angle DCE = CER (alternative interior angle) eq-1
➩angle CER = CEB + BER
➩angle 100° = 40° + BER
➩BER = 100-40
➩BER = 60° (eq - 2)
➩angle ABE + BER = 180° ( co - interior angel)
➩ABE = 180° - BER
➩ABE = 180° - 60°
➩ABE = 120°
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