in fig 6 find angle ACD
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In ∆ABC,
Angle A = 58°
Angle B = 62°
[ Sum of all angles of a triangle is equal to 180°]
angle A + angle B + angle C = 180°
58° + 62° + angle C = 180°
120° + angle C = 180°
angle C = 180° - 120°
angle C = 60°
{ Note :- interior C = 62° }
For Exterior C,
CD is is a straight line which is equal to 180°
60° + angle C = 180°
angle C = 180° - 60°
angle C = 120°
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