In Fig. 60, AB and CD are parallel lines intersected by a transversal by a transversal PQ at L and M respectively. If ∠LMD = 35∘ find ∠ALM and ∠PLA.
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Answered by
14
∠ALM = ∠LMD = 35° [Alternate Angles]
∠ALM + ∠PLA = 180° [Linear pair]
Hence, ∠PLA = 180° - 35° = 145°
Answered by
7
AB ll CD and line PQ is the transversal
by altranet angle
angle LMD=angle ALM
angle ALM=35
angleLMD +angleMLB =180 (INTERIOR
ANGLE)
35+ angle MLB=180
angle MLB =180- 35
AngleMLB = 145
angle PLA =angle MLB (vertically opposite angle )
angle PLA = 145
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