In fig.7.144,we have AB||CD||EF.If AB=6cm,CD=x cm,EF=10cm,BD=4cm and DE=y cm,calculate the value of x and y.
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Answer:
consider triangle ADB and triangle EDF
angle ADB=angle EDF (vertical angles)
angle ABD=angle FED(alternate angles)
angle BAD=angle EFD(alternate angles)
therefore, triangle ADB=triangle EDF(by AA similarity)
BD/DE=AB/FE
4/y=6/10
y=40/6=20/3
y=6.67cm
similarly, triangle ADE is similar to triangle CDE
DE/BE=DC/AB
6.67/10.67=x/6
x=6×6.67/10.67
x=3.75cm
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