Question

In fig. 7. 21 , Ac= AE , AB = AD and ∆BAD = ∆ EAC . show that BC=DE​

Answer 1

Answer:

here is answer

Step-by-step explanation:

It is given that ∠BAD=∠EAC

∠BAD+∠DAC=∠EAC+∠DAC [add ∠DAC on both sides]

∴∠BAC=∠DAE

In △BAC and △DAE

AB=AD (Given)

∠BAC=∠DAE (Proved above)

AC=AE (Given)

∴△BAC≅△DAE (By SAS congruence rule)

∴BC=DE (By CPCT)