Question

In Fig. 7.49,2 angle B< angleA and angleC< angleD. Show that
AD<BC.​

Answer 1

Answer:

$\huge{\underline{\mathtt{\red{❥A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$ANSWER

In △AOB,

∠B<∠A

∴AO<BO

∴ Side opposite to the greater angle is longer.

In △COD,

∠C<∠D⇒OD<OC

⇒AO+OD<OB+OC

∴AD<BC