Question

In Fig. 7.49, B<A and C<D. Show that
AD<BC.​

Answer 1

Answer:

Let the point of intersection of BC and AD be O

In △ABO

⇒∠B<∠A

Thereore, ⇒AO<BO (1) (side opposite to greater angle is largest)

Similarly,

In △COD

⇒∠C<∠D

Thereore, ⇒DO<CO (2) (side opposite to greater angle is largest)

Adding (1) and (2) we get,

⇒BO+OC>AO+DO

⇒BC>AD