Question

in fig. 7.58, ABC is a ∆ in which AB = AC and AD is an altitude on BC. Prove that AD bisects ✓A​

Answer 1

Answer:

ABC is an isosceles △.

AB=AC

AD is altitude

.

∠ADB=∠ADC=90°

To prove:-

(i) AD bisects BC, i.e., BD=CD

(ii) AD bisects ∠A, i.e., ∠BAD=∠CAD

Proof:-

In △ADB and △ADC,

∠ADB=∠ADC[Each 90°]

AB=AC[Given]

AD=AD[Common]

By R.H.S congruency,

△ADB≅△ADC

By C.P.C.T.

BD=CD

∠BAC=∠CAD

Hence proved.

Answer 2

Please mark my answer brainest

Hope it will help