Question

In fig. 7, are shown two arcs paq and pbq. arc paq is a part of circle with centre o and radius op while arc pbq is a semi-circle drawn on pq as diameter with centre m. if op = pq = 10 cm show that area of shaded region is

Answer 1

Area of first semicircle

A = pi/2 r^2
    = 157.14
Area of circle

a = pi* 100
   = 314.28
Thus total area

T = A + a
   = 314.28 + 157.14
   = 471.42

Answer 2

here your answer
____________________
OP=PQ=QO=10cm
Triangle POQ is an equilateral triangle
therefore angle POQ =60°
Ar.of segment =PAQM
= theta/360πr²-√3/4a²
=60/360π×10²-√3/4×10²
=10²[π/6-√3/4]
=[100π/6-100√3/4] cm²
Ar. of semicircle π/2(5)²
=25π/2cm²
Ar. of shaded region =25π/2-(50π/3-25√3)
=25π/2+25√3
=25π/6+25√3
=25(√3-π/6) cm²
____________________
I Hope it will help u
____________________
PLS MARK AS BRAINLIST