Question

. In Fig. 8.13. ſind tan P-cot R.​

Answer 1

I hope it may be helpful to you

Answer 2

Given:-

• PQ = 12 c.m.,
• PR = 13 c.m.,

To Find: tan P - cot R.

As per the Pythagoras theorem,

PR² = PQ² + QR²

→ (13)² = (12)² + QR²

→ QR² = (13)² - (12)²

→ QR² = (13 + 12)(13 - 12)

→ QR² = 25

→ QR = √25 = 5

So, QR = 5 c.m.

Here,

tan P

= (Opposite side of angle P)/(Adjacent side of angle P)

= QR/PQ

= (5 c.m.)/(12 c.m.)

= 5/12

Also,

cot R

= 1/(tan R)

= 1/(Opposite side of angle R)/(Adjacent side of angle R)

= (Adjacent side of angle R)/(Opposite side of angle R)

= QR/PQ

= (5 c.m.)/(12 c.m.)

= 5/12

∴ tan P - cot R

= 5/12 - 5/12

= 0 ...(Ans.)