Question

in fig 8.5, ∆ABC is isosceles with AB=AC. Find the values of x and y. ​

Answer 1

Given:-

• ∆ABC is isosceles with AB = AC

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To find:-

• Values of x and y.

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Solution:-

★ Finding ∆ABC

$\large{\tt{\longmapsto{\triangle ABC = (180° - 30°) \div 2}}}$

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$\large{\tt{\longmapsto{150° \div 2}}}$

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$\boxed{\large{\tt{\longmapsto{\red{\triangle ABC = 75°}}}}}$

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★ Finding X

$\large{\tt{\longmapsto{}}}$$\large{\tt{\longmapsto{x = 180° - \triangle ABC}}}$

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$\large{\tt{\longmapsto{x = 180° - 75°}}}$

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$\boxed{\large{\tt{\longmapsto{\red{x = 105°}}}}}$

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★ Finding Y

$\large{\tt{\longmapsto{y = 180° - \triangle ABC}}}$

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$\large{\tt{\longmapsto{y = 180° - 75°}}}$

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$\boxed{\large{\tt{\longmapsto{\red{y = 105°}}}}}$

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Hence,

Value of x = 105°

Value of y = 105°

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Answer 2

Answer:

Motu's share of profit is Rs. 2,000

Patalu's share of profit is Rs. 4,000

Explanation:

Given :

Money invested for starting the business by Motu = Rs 10,000

Patalu invested money = Rs 20,000

Profit received at the end of the year = Rs 6,000

To find :

Share of profits for each partner of respectively

Solution :

Motu's Share = 10,000 × 12

⇒ 1,20,000

Patalu's Share = 20,000 × 12

⇒ 2,40,000

⇒ 12 : 24

★ Motu's Share : Patalu's Share

⇒ 1 : 2

★ Total Profit = Rs 6,000

Motu's Share = $\tt{\dfrac{1}{3} \: \times \: 6,000}$

⇒ 2,000

Patalu's Share =$\tt{\dfrac{2}{3} \times 6,000}$

⇒ 4,000

Therefore,

Motu's share of profit is Rs. 2,000

Motu's share of profit is Rs. 2,000Patalu's share of profit is Rs. 4,000