in fig. 8.5 triangle ABC is an isosceles with AB = AC. find the value of X and Y
please don't give wrong Answer
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∠ABC and x are on a straight line
⇒ both angles add up to 180º
x = 180 - ∠ABC
x = 180 - 75 = 105º
∠ACB = ∠ABC = 75º
∠ACB and y are on a straight line
⇒ both angles add up to 180º
y = 180 - ∠ACB
y = 180 - 75 = 105º
hope it helps
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Angle ABO+ x° = 180° (straight line)
75°+x°=180°
x°= 105°
Angle AOB+y°=180° ( straight line)
75°+y°=180°
y°=105°
Hence, y°=105° x°=105°
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