In Fig. 8.7, AB = AC and....AP is perpendicular to BC and angle.B = 60°. Then find (i) angle.BAP (ii) angle.ACB.
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1.) Angle B = 60°
Angle P = Right angle = 90°
Angle A+B+C = 180°( sum of interior angles of a triangle)
Angle = 180°-(60°+90°)
Angle A = 30°
i.e. Angle B = 60°, A = 30° and P = 90°
2.) Angle B = 60°
Angle C = Angle B = 60°
Angle A = 180°-(60°+60°)
Angle A = 60°
i.e Angle A,C and B = 60°
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