in fig. 9.15 ABCD is a parallelogram AE | DC and CF| AD . IF AB 16 cm AE 8 cm and CF10 cm find AD.
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area of parallelogram is base into height and AB is equal to DC o area of the parallelogram is AE X DC = 16X8 and area of para. is also base x height = AD x FC = 10 X AD. now by comparing both the results we get AD is equal to 16 X 8 / 10 that is 12.8
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Question :-
In figure, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD.
Answer :-
We have, AE ⊥ DC and AB = 16 cm
∵ AB = CD [Opposite sides of parallelogram]
∴ CD = 16 cm
Now, area of parallelogram ABCD = CD x AE
= (16 x 8) cm2 = 128 cm2 [∵ AE = 8 cm]
Since, CF ⊥ AD
∴ Area of parallelogram ABCD = AD x CF
⇒ AD x CF = 128 cm
⇒ AD x 10 cm = 128 cm2 [∵ CF= 10 cm]
⇒ AD = 128/10 cm = 12.8 cm 10
Thus, the required length of AD is 12.8 cm
Hope it helps ❤ Mrk as brainliest
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