Math, asked by Anonymous, 1 month ago

In Fig. 9.15, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD ??

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Answers

Answered by bansalraghav528
19

Answer:

In parallelogram ABCD, we have given AB=10cm, AE=8cm, and CF=12cm.

⇒ AB=DC=10cm [Opposite sides of parallelogram are equal]

⇒ Lets find out area of parallelogram with height AE and base DC.

⇒ Area of parallelogram ABCD=b×h

⇒ Area of parallelogram ABCD=DC×AE

⇒ 10×8

∴ Area of parallelogram ABCD=80cm

2

--- ( 1 )

⇒ Now, to find area of parallelogram let CF be the height and AD will be base.

⇒ Area of parallelogram ABCD=CF×AD

⇒ 80=12×AD [From ( 1 )]

⇒ AD=

12

80

∴ AD=6.66cm

Answered by itzgeniusgirl
37

question :-

In Fig. 9.15, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD ??

formula :-

Area of parallelogram = Base × Altitude

solution :-

AB = CD = 16 cm (Opposite sides of a parallelogram)

CF = 10 cm and AE = 8 cm

Now,

Area of parallelogram = Base × Altitude

= CD×AE = AD×CF

⇒ 16×8 = AD×10

⇒ AD = 128/10 cm

⇒ AD = 12.8 cm

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