Question

In Fig. 9.2. PQ is a
chord of a circle and PT is the tangent at P
such that ZQPT = 60°. Then ZPRQ is equal
to
(B) 150°
(D) 110°
(A). 135°
(C) 120°
​

Answer 1

Answer:

120 is the answer

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Answer 2

Hey mate!!!

I think the answer is c. 120°

Hope it helps...

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