Question

In fig 9.28 , AP || BQ || CR. Prove that ar (AQC) = ar (PBR)​

Answer 1

$\huge\sf{ \underline{ \underline{Given :-}}}$

AP || BQ || CR

$\huge\sf{ \underline{ \underline{To Prove :-}}}$ area of triangle ACQ = area of triangle PBR

$\huge\sf{ \underline{ \underline{Proof :}}}$

Since triangle ABQ and triangle PBQ are on same base BQ and between || lines BQ and AP

therefore , area of triangle ABQ = area of triangle PBQ..... -(1)

Also triangle CBQ and triangle RBQ are on same base BQ and b/w | | lines BQ and CR

therefore , area of triangle CBQ = area of triangle RBQ ..... -(2)

Add (1) and (2)

area of (ABQ + CBQ) = area of (PBQ + RBO)

area of triangle ACQ = area of triangle PBR

Answer 2

Refer The Attachment ⬆️

Hope It Helps You ✌️