In Fig. 9.40, if AB||CD, EF||BC, ∠BAC = 65° and ∠DHF = 35°, find ∠AGH.
Answers
In Fig. 9.40, if AB||CD, EF||BC, ∠BAC = 65° and ∠DHF = 35°, then
∠AGH = 100°
Given,
AB||CD
EF||BC
∠ BAC = 65°
∠ DHF = 35°
To find : ∠ AGH
Proof:
Consider the attached figure while going through the following steps
∠ DHF = ∠ GHC (vertically opposite angles are equal)
as ∠ DHF = 35°
∴ ∠ GHC = 35°
∠ BAC = ∠ ACD (vertically opposite angles are equal)
as ∠ BAC = 65°
∴ ∠ ACD = 65°
∠ HCG = ∠ BAC = 65° (angles forming a linear pair are supplementary)
In Δ GHC
∠ GHC + ∠ HCG + ∠ CGH = 180°
35° + 65° + ∠ CGH = 180°
100° + ∠ CGH = 180°
∠ CGH = 180° - 100°
∴ ∠ CGH = 80°
Given, AGC is a straight line.
∠ CGH + ∠ AGH = 180°
80° + ∠ AGH = 180°
∠ AGH = 180° - 80°
∴ ∠ AGH = 100°
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