Math, asked by sonusimmba2107, 4 months ago

In Fig. 9.42, AB and CD are two lines intersecting at O. If angleAOC= 35° and angleCOE = 30°, find the values of x, y and z.​

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Answers

Answered by thanushiya72
12

Step-by-step explanation:

Hope this helps u.....

I did this prblm with the concept of linear pair...which means the angle of a line is 180...

x=145

y=115

z=35

Incase of steps required...refer the attachment......

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Answered by REDPLANET
63

\underline{\boxed{\bold{Question}}}  

In Fig. 9.42, AB and CD are two lines intersecting at O. If ∠AOC= 35° and ∠COE = 30°, find the values of x, y and z.​

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\underline{\boxed{\bold{Important\;Information}}}  

Vertically opposite angles are angles formed by 2 straight line which are exactly opposite and they are equal.

Sum of linear pair of angles = 180°

↠ Refer attachment for clear figure.

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\underline{\boxed{\bold{Given}}}

∠AOC= 35°

∠COE = 30°

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\underline{\boxed{\bold{Answer}}}

Let's Start !

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✰ As sum of angles formed on straight line = 180° (Linear Pair)

:\implies \angle AOC +  \angle DOA = 180^{\circ}

:\implies 35^{\circ} +  x = 180^{\circ}

:\implies  x = 180^{\circ} -  35^{\circ}

\boxed{\red{ :\implies  x = 145^{\circ} } }

✰ As by vertically opposite angles

:\implies  \angle DOA = \angle COE + \angle EOB

:\implies  145^{\circ}  = 30^{\circ} + y

:\implies   y = 145^{\circ}  - 30^{\circ}

\boxed{ \red{:\implies   y = 115^{\circ} } }

✰ As by vertically opposite angles

:\implies  \angle BOD = \angle AOC

:\implies  z = 35^{\circ}

\boxed{ \red{:\implies   z = 35^{\circ} } }

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\underline{\boxed{\bold{\bigstar \; Verification \; \bigstar}}}

Sum of all angle formed in circular loop is 360°

:\implies  \angle BOD +  \angle BOE +  \angle EOC +  \angle COA +  \angle AOD = 360^{\circ}

:\implies z +  y +  30^{\circ} +  35^{\circ} +  x = 360^{\circ}

:\implies 35^{\circ} +  115^{\circ} +  30^{\circ} +  35^{\circ} +  145^{\circ} = 360^{\circ}

:\implies 360^{\circ} = 360^{\circ}

\boxed {\bold{\blue{LHS = RHS} } }

Hence Verified.

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\boxed{\boxed{\bold{\therefore Measure \; of \; \angle x = 145^{\circ}}}}

\boxed{\boxed{\bold{\therefore Measure \; of \; \angle y = 115^{\circ}}}}

\boxed{\boxed{\bold{\therefore Measure \; of \; \angle z = 35^{\circ}}}}

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Hope this helps u.../

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