In Fig. 9.42. side BC of ∆ABC is produced to point D such that bisectors of
angle ABC and angle ACD meet at a point E. If angle BAC = 68°, find angle BEC
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bac =ecb alternate angle then be
let abc consider x
68+68+x=180
x=136 -180 =44
ecb=68
ABC=bec
so it = 44
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