Question

In fig.9.44 , ABC is an isosceles triangle in which AB=AC. Also , D is a point such that BD=CD. Prove that AD bisects ∆A and ∆D.

Answer 1

Given,
∆ ABC is an isosceles triangle in which AB = AC,BD = CD
To prove:- angle BAD =CAD and BDA= CDA
Proof:- In ∆BAD and ∆ CAD

AB=AC (given)
BDA=DAC (alternate angles)
AD=AD (common)
Therefore, ∆BAD=∆CAD {SAS rule}
=> BAD=CAD (cpct)
=> BDA=CDA {proved}
Thus, AD bisects ∆A as well as ∆D
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Answer 2

Answer:

this is an isosceles triangle in which AD is bisecting the ∆ACD and ∆ABD

Step-by-step explanation:

THEN SO IN COMMON SENSE WE KNOW THAT AD IS ALSO BISECTING THE ANGLE A AND ANGLE D THIS IS PROVED THOSE QUESTIONS YOU HAVE ANY DOUBT SO PLEASE MARK IT BRAINLIEST AND PRESS THE THANK YOU BUTTON¥