Question

In fig.a tent is in the shape of a cylinder surmounted by a conical top of same diameter. If the height and the radius of a cylindrical part are 2.1 M and 2m and slant height of conical part is 2.8 M .find the area of Canvas used to make the tent. Also find the cost of the canvas of the tent at rate of 500 /- per m2

Answer 1

Step-by-step explanation:

CSA of cylinder is = 2πr(r+l)

2*22/7*2(2+2.8)

After solving it multiple it by 500

Answer 2

$\huge\blue{Answer}$

[FIGURE IS IN THE ATTACHMENT]

SOLUTION;

Given:

Height (h) of the cylindrical part = 2.1 m

Diameter of the cylindrical part = 3 m

Radius of the cylindrical part = 3/2 m

Slant height (l) of conical part = 2.8 m

Total canvas used = CSA of conical part + CSA of cylindrical part

= πrl + 2πrh

= πr(2h+l)

= (22/7)×3/2(2×2.1+2.8)

= (22/7)×3/2(4.2+2.8)

= (22/7)×3/2(7)

= 11×3

= 33 m²

Cost of 1 m² canvas = ₹ 500

Cost of 44 m² canvas = 33 × 500 = 16500

The cost of Canvas needed to make the tent= ₹ 16500

Hence, it will cost ₹ 16500 for making such a tent.

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