Question

In Fig. AB= AC and AD is the bisector of
ZBAC.
State three pairs of equal parts
in triangles ADB and ADC.
(ii): Is AADB AADC? Give
reasons
Is B= 2C? Give reasons.​

Answer 1

Here in \Delta ADB and \Delta ADC.

i) Three pair of equal parts are:

AD = AD ( common side )

BD = CD ( as d is the mid point of BC)

AB = AC (given in the question)

ii) Now,

by SSS Congruency rule,

\Delta ADB\cong \Delta ADC

iii) As both triangles are congruent to each other we can compare them and say

\angle B = \angle C.