Question

in fig , AB = AC , angel ACM = 125° and angel PAB = x° find the value of x​

Answer 1

Given :- in fig , AB = AC , angel ACM = 125° and angel CAB = x° . find the value of x ?

Solution :-

in ∆ABC,

→ AB = AC

So,

→ ∠ABC = ∠ACB (Angle opposite to equal sides are equal.)

Now,

→ ∠ACM + ∠ACB = 180° (Linear pair.)

→ 125° + ∠ACB = 180°

→ ∠ACB = 180° - 125°

→ ∠ACB = 55°

So,

→ ∠ABC = ∠ACB = 55°

Now,

→ ∠ABC + ∠ACB + ∠BAC = 180° (angle sum property.)

→ 55° + 55° + ∠x = 180°

→ ∠x = 180° - 110°

→ ∠x = 70° (Ans.)

Learn more :-

show that in a triangle ABC the exterior angle bisector of Angle B and C inclined at an angle 90 -A/ 2

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Answer 2

Step-by-step explanation:

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