✨✔️ In Fig. AB and CD are two diameters of a circle (with centre O) perpendicular to each other and OD is the diameter of the smaller circle. If OA = 7cm, Find the area of shaded region.
Attachments:
Answers
Answered by
26
Area of sector OBC= pie r^2/4
OB = OC = OA = OD= r = 7
area of sector = 22/7 × 7 × 7 × 1/4
= 154/4 = 38.5
Area of right angled OBC = 1/2 × r × r = 1/2 × 7 × 7
= 49/2 = 24.5
Now area of one shaded region = 38.5 -24.5 = 14
Same way area of shaded region under CA = 14
area of circle with OD as diameter = pie r^2
= 22/7 × 7 /2× 7/2
= 154/4 = 38.5
So area of whole shaded = 14 + 14 +38.5 = 28+ 38.5 = 66.5 cm^2
OB = OC = OA = OD= r = 7
area of sector = 22/7 × 7 × 7 × 1/4
= 154/4 = 38.5
Area of right angled OBC = 1/2 × r × r = 1/2 × 7 × 7
= 49/2 = 24.5
Now area of one shaded region = 38.5 -24.5 = 14
Same way area of shaded region under CA = 14
area of circle with OD as diameter = pie r^2
= 22/7 × 7 /2× 7/2
= 154/4 = 38.5
So area of whole shaded = 14 + 14 +38.5 = 28+ 38.5 = 66.5 cm^2
TEJ1977:
hmm myself Tej
Answered by
28
ANSWER
AREA OF SHADED REGION
66.5 CM^2
I HOPE THIS INFO HELPS YOU ☺️☺️☺️☺️
AREA OF SHADED REGION
66.5 CM^2
I HOPE THIS INFO HELPS YOU ☺️☺️☺️☺️
Attachments:
Similar questions