Question

In Fig. AB and CD are two equal chords of a circle with centre O. OP and OQ are perpendiculars on chords AB and CD respectively. If angle POQ = 150° then Angle APQ is equal to​

Answer 1

POQ+PQO+OPQ=180

AND ; POQ IS 150° THEN BOTH ANGELS ARE 15°

THEN APO IS 90° WE KNOW OPQ =15 THEN APO IS 90° APQ+APO= 90° THEN APQ+15=90 AFTER

APQ=90-15=75°